Plots Interpretation - Scan-and-Solve for Rhino2024-03-29T06:09:00Zhttp://www.scan-and-solve.com/forum/topics/plots-interpretation?commentId=6083097%3AComment%3A34143&feed=yes&xn_auth=noHI:
I guess I'm thinking of…tag:www.scan-and-solve.com,2012-05-25:6083097:Comment:342612012-05-25T15:17:39.992ZBob Johanssonhttp://www.scan-and-solve.com/profile/BobJohansson507
<p>HI:</p>
<p> </p>
<p>I guess I'm thinking of a beam with depth and you are thinking of a flat panel</p>
<p>which would be a layer in a composite, so here is my reference so we are comparing apples</p>
<p>and apples. I will try a calculation and post it with the eqivalent in SnS and see how I do.…</p>
<p><a href="http://storage.ning.com/topology/rest/1.0/file/get/2506634059?profile=original" target="_self"><img class="align-center" src="http://storage.ning.com/topology/rest/1.0/file/get/2506634059?profile=original" width="158"></img></a></p>
<p>HI:</p>
<p> </p>
<p>I guess I'm thinking of a beam with depth and you are thinking of a flat panel</p>
<p>which would be a layer in a composite, so here is my reference so we are comparing apples</p>
<p>and apples. I will try a calculation and post it with the eqivalent in SnS and see how I do.</p>
<p><a href="http://storage.ning.com/topology/rest/1.0/file/get/2506634059?profile=original" target="_self"><img class="align-center" src="http://storage.ning.com/topology/rest/1.0/file/get/2506634059?profile=original" width="158"/></a></p>
<p> </p>
<p> </p>
<p> </p> My believe is that it is not…tag:www.scan-and-solve.com,2012-05-25:6083097:Comment:343502012-05-25T07:44:14.306ZJose Cristoshttp://www.scan-and-solve.com/profile/JoseCristos
<p>My believe is that it is not t= thickness but b=beam width.</p>
<p></p>
<p>It would be brilliant if Mike could give us his thoughts!</p>
<p></p>
<p>My believe is that it is not t= thickness but b=beam width.</p>
<p></p>
<p>It would be brilliant if Mike could give us his thoughts!</p>
<p></p> HI:
I have experienced simi…tag:www.scan-and-solve.com,2012-05-25:6083097:Comment:341432012-05-25T06:21:53.902ZBob Johanssonhttp://www.scan-and-solve.com/profile/BobJohansson507
<p>HI:</p>
<p> </p>
<p>I have experienced similar problem discrepancies between my computer analysis and</p>
<p>hand calculations which I used to check my results on various projects. Previously, I found the problem</p>
<p>was the way I was contraining or holding the parts between the two models were different.</p>
<p>(Simply suported versus fixed or clamped). I havent used SnS to look at shear stress in this way</p>
<p>but I could give it a go and get back to…</p>
<p>HI:</p>
<p> </p>
<p>I have experienced similar problem discrepancies between my computer analysis and</p>
<p>hand calculations which I used to check my results on various projects. Previously, I found the problem</p>
<p>was the way I was contraining or holding the parts between the two models were different.</p>
<p>(Simply suported versus fixed or clamped). I havent used SnS to look at shear stress in this way</p>
<p>but I could give it a go and get back to you.</p>
<p> </p>
<p>Bob</p>
<p> </p> Sorry, that was a typo
T =…tag:www.scan-and-solve.com,2012-05-24:6083097:Comment:342582012-05-24T15:08:15.769ZBob Johanssonhttp://www.scan-and-solve.com/profile/BobJohansson507
<p>Sorry, that was a typo</p>
<p> </p>
<p>T = VQ/It</p>
<p> </p>
<p>it was a bad hair day.</p>
<p> </p>
<p>Mike probably has lots to say about shear stress</p>
<p>because its his specialty.</p>
<p> </p>
<p> </p>
<p>Sorry, that was a typo</p>
<p> </p>
<p>T = VQ/It</p>
<p> </p>
<p>it was a bad hair day.</p>
<p> </p>
<p>Mike probably has lots to say about shear stress</p>
<p>because its his specialty.</p>
<p> </p>
<p> </p> Yes, like in a panel suported…tag:www.scan-and-solve.com,2012-05-24:6083097:Comment:340852012-05-24T13:43:52.134ZJose Cristoshttp://www.scan-and-solve.com/profile/JoseCristos
<p>Yes, like in a panel suported at four sides. Then we have Sxz and Syz.</p>
<p>Yes, like in a panel suported at four sides. Then we have Sxz and Syz.</p> Hi Bob: Thanks for your repl…tag:www.scan-and-solve.com,2012-05-24:6083097:Comment:342552012-05-24T13:43:02.070ZJose Cristoshttp://www.scan-and-solve.com/profile/JoseCristos
<p>Hi Bob:<br></br> <br></br> Thanks for your reply. Yes I agree with you. Just replace the T at the denominator for beam width.<br></br> <br></br> If the beam is in the X direction and the thickness in Z, then this shear is Sxz, "out-of plane shear", usually called.<br></br> At a particular point of a particular beam section, shear in the horizontal plane is the same as the one in vertical plane (for equilibrium).<br></br> <br></br> In isoptropic materials, it reaches its maximum at the centreline of thickness, following…</p>
<p>Hi Bob:<br/> <br/> Thanks for your reply. Yes I agree with you. Just replace the T at the denominator for beam width.<br/> <br/> If the beam is in the X direction and the thickness in Z, then this shear is Sxz, "out-of plane shear", usually called.<br/> At a particular point of a particular beam section, shear in the horizontal plane is the same as the one in vertical plane (for equilibrium).<br/> <br/> In isoptropic materials, it reaches its maximum at the centreline of thickness, following a parabolic law from top to centreline.<br/> In anisotropic materials, its value depends on the relative stiffness (EI) of the layers on top in respect to global beam stiffness and can be elsewhere.<br/> This value is often difficult to obtain even with FEA, so it would be of great help if SnS can deliver it, even as an isotropic. Also provides an idea of the importance of "shear deflection".<br/> <br/> My concerns are relatively to the plots obtained by SnS compared to analytical (Sx, deflection and Sxz) for this 40x220x12.4 mm AISI 304 clamped cantilever beam. Maybe I´m wrong with my analytical or the boundary conditions input, but discrepancy is huge...maybe you can help me.<br/> I correct my analytical max Sxz at the clamping section to 55 MPa.<br/> <br/> Cheers!<br/> Jose</p> If the stress element is thre…tag:www.scan-and-solve.com,2012-05-23:6083097:Comment:340812012-05-23T19:42:37.243ZBob Johanssonhttp://www.scan-and-solve.com/profile/BobJohansson507
<p>If the stress element is three dimensional then there</p>
<p>would be horizontal shear in two horizontal directions</p>
<p>providing for static equalibriaum.</p>
<p>If the stress element is three dimensional then there</p>
<p>would be horizontal shear in two horizontal directions</p>
<p>providing for static equalibriaum.</p> Looking at a stress element i…tag:www.scan-and-solve.com,2012-05-23:6083097:Comment:341362012-05-23T17:22:13.429ZBob Johanssonhttp://www.scan-and-solve.com/profile/BobJohansson507
<div class="xg_user_generated"><p>Looking at a stress element in a beam loaded under vertical shear, there has to be a horizontal shear component to offset the vertical shear for static equalibrium to occur</p>
<p> </p>
<p><a href="http://storage.ning.com/topology/rest/1.0/file/get/2506633843?profile=original" target="_self"><img class="align-full" src="http://storage.ning.com/topology/rest/1.0/file/get/2506633843?profile=original" width="535"/></a></p>
</div>
<div class="xg_user_generated"><p>Looking at a stress element in a beam loaded under vertical shear, there has to be a horizontal shear component to offset the vertical shear for static equalibrium to occur</p>
<p> </p>
<p><a href="http://storage.ning.com/topology/rest/1.0/file/get/2506633843?profile=original" target="_self"><img class="align-full" src="http://storage.ning.com/topology/rest/1.0/file/get/2506633843?profile=original" width="535"/></a></p>
</div> Are you asking about the mean…tag:www.scan-and-solve.com,2012-05-23:6083097:Comment:343402012-05-23T16:27:06.641ZBob Johanssonhttp://www.scan-and-solve.com/profile/BobJohansson507
<p>Are you asking about the meaning of the horizontal shear stress that exists in a</p>
<p>beam? This is important in composite beams because each layer of the beam is fastened</p>
<p>together and the strength of the fastening mechanisim has to be sufficient to withstand the</p>
<p>horizontal stress.</p>
<p> </p>
<p>The horizontal shear stress is usually caculated using the general shea formula</p>
<p> </p>
<p>T = VQ/IT</p>
<p> </p>
<p>where V = vertical shearing force</p>
<p>I = moment of…</p>
<p>Are you asking about the meaning of the horizontal shear stress that exists in a</p>
<p>beam? This is important in composite beams because each layer of the beam is fastened</p>
<p>together and the strength of the fastening mechanisim has to be sufficient to withstand the</p>
<p>horizontal stress.</p>
<p> </p>
<p>The horizontal shear stress is usually caculated using the general shea formula</p>
<p> </p>
<p>T = VQ/IT</p>
<p> </p>
<p>where V = vertical shearing force</p>
<p>I = moment of inertia</p>
<p>t = thickness</p>
<p>Q = Statical moment</p>